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Pages: < 1 � 3332 3333 3334 3335 3336 … 3570 >

[2014-10-07. : 2:47 am]

Devourer -- RTS > MOBA

[2014-10-07. : 2:47 am]

Arkane -- I'm mostly exclusive to RTS

[2014-10-07. : 2:47 am]

Devourer -- You can run away from heroes with no worries at all

[2014-10-07. : 2:47 am]

Arkane -- I dont even play MOBAs

[2014-10-07. : 2:47 am]

Devourer -- Basically, every spell in LoL is limited to like, approximated, 300 pixels at most

[2014-10-07. : 2:47 am]

Arkane -- :^)

[2014-10-07. : 2:47 am]

Devourer -- HoN as in action and graphics, to me, is superior to LoL

[2014-10-07. : 2:47 am]

Arkane -- Heroes of Newerth is LoL for hipsters

[2014-10-07. : 2:46 am]

Devourer -- I wished S2 wasn't so incredibly incompetent to balance a game.

[2014-10-07. : 2:46 am]

Arkane -- NO MANA FFS

[2014-10-07. : 2:46 am]

Arkane -- NO IM MID

[2014-10-07. : 2:46 am]

Arkane -- GONNA GO MID

[2014-10-07. : 2:46 am]

Arkane -- STUN STUN STUN

[2014-10-07. : 2:46 am]

Arkane -- league of legends is where its at

[2014-10-07. : 2:46 am]

Arkane -- starcraft is worst game 2014

[2014-10-07. : 2:45 am]

Moose -- Disclaimer: may or may not be the most efficient method

[2014-10-07. : 2:45 am]

Moose -- Use A^-1

[2014-10-07. : 2:37 am]

MasterJohnny -- Suppose A is nxn and nonsingular and B is nxm how do I efficiently solve AX=B

[2014-10-07. : 2:30 am]

Dem0n -- l)ark_ssj9kevin

l)ark_ssj9kevin shouted: if you haven't made your OWN shortcut keys, you don't truly know all the shortcut keys.

I have not. I'm still using shift+insert to paste D:

[2014-10-07. : 2:27 am]

jjf28 -- rofl the van idea (if you've seen the new big bang theory) :lol:

[2014-10-07. : 2:03 am]

Moose -- But yeah, try xemacs instead.

[2014-10-07. : 2:00 am]

Moose -- It's true, if only because there are too damn many in that program.

[2014-10-07. : 1:57 am]

l)ark_ssj9kevin -- if you haven't made your OWN shortcut keys, you don't truly know all the shortcut keys.

[2014-10-07. : 1:54 am]

Moose -- You just mad you don't know all the shortcut keys.

[2014-10-07. : 1:53 am]

l)ark_ssj9kevin -- why are you using emacs

[2014-10-07. : 1:41 am]

Dem0n -- Emacs is such a piece of shit.

[2014-10-07. : 1:36 am]

trgk -- https://raw.githubusercontent.com/bwapi/bwapi/master/bwapi/BWAPI/Source/BW/CUnit.h

[2014-10-07. : 1:34 am]

jjf28 -- void pointer to memory, defined offsets, duh

[2014-10-07. : 1:30 am]

Roy -- Or, more importantly, how you'd try to manage an array of groups of variables without using structs.

[2014-10-07. : 1:08 am]

jjf28 -- (was going to say "then think how ugly a function call with that would be" but that's not what you meant by not seeing a diff

)

[2014-10-07. : 1:05 am]

Dem0n -- Oh, didn't see the full picture

[2014-10-07. : 1:05 am]

jjf28 -- imagine if your struct would otherwise be 8 variables

[2014-10-07. : 1:04 am]

Dem0n -- I don't see a difference between using structs and not using them

[2014-10-07. : 1:00 am]

jjf28 -- meh

[2014-10-07. : 1:00 am]

jjf28 -- woops, failed with semicolons

[2014-10-07. : 1:00 am]

jjf28 -- http://puu.sh/c2mpt/ad13ab85ff.png

[2014-10-07. : 1:00 am]

jjf28 -- disregard last picture

[2014-10-07. : 12:59 am]

jjf28 -- woops

[2014-10-07. : 12:59 am]

jjf28 -- http://puu.sh/c2mkz/1c18e84bb9.png

[2014-10-07. : 12:57 am]

jjf28 -- http://puu.sh/c2meW/1591bab15c.png

[2014-10-07. : 12:52 am]

trgk -- struct = Merge multiple variables into one.

[2014-10-07. : 12:49 am]

Dem0n -- someone teach me wtf structs in C are pls

[2014-10-07. : 12:43 am]

jjf28 -- awake for 32 hours, brain has reached mush max

[2014-10-06. : 10:32 pm]

Moose -- Yeah, you can optionally add a "rekt" after the GG.

[2014-10-06. : 10:29 pm]

Jack -- tyrannasaurus rekt :wob:

[2014-10-06. : 10:03 pm]

Moose -- Proof by contradiction. Assume x > 0 does not imply (1/x) > 0, then x > 0 must imply (1/x) <= 0. Since x > 0, you can multiply both sides by x without reversing the inequality, so (1/x) * x <= 0 * x. Since x != 0, that becomes 1 <= 0. Contradiction, GG. ∎

[2014-10-06. : 9:29 pm]

Moose -- Zoan

Zoan shouted: btw, how do you prove [ x > 0 ] => [ (1/x) > 0 ]

Uh, did you try multiplying both sides by x?

[2014-10-06. : 9:24 pm]

KrayZee -- :wob:

[2014-10-06. : 8:31 pm]

jjf28 -- i*

[2014-10-06. : 8:23 pm]

Generalpie -- 1V + 1 = V

[2014-10-06. : 8:23 pm]

Generalpie -- 111+ 1 = 1V

[2014-10-06. : 8:23 pm]

Generalpie -- 11 + 1 = 111

[2014-10-06. : 8:22 pm]

Generalpie -- 1+ 1 = 11

[2014-10-06. : 7:20 pm]

Zoan -- you'd have to prove that too D:

[2014-10-06. : 7:18 pm]

sigsaucy -- 1/x^2 * x = x/x^2 = 1/x

[2014-10-06. : 7:17 pm]

Zoan -- but why is 1/x^2 * x = 1/x ?

[2014-10-06. : 7:16 pm]

sigsaucy -- x > 0 <====> 1/x^2 * x > 1/x^2 * 0 <====> 1/x > 0

[2014-10-06. : 7:10 pm]

sigsaucy -- x > 0 => 1/x^2 x > 1/x^2 0 => 1/x > 0

[2014-10-06. : 6:54 pm]

Zoan -- I feel like there's a simpler way to do this though..

[2014-10-06. : 6:52 pm]

Zoan -- ohhh, I need to specify that 1/(x*x) > 0

[2014-10-06. : 6:46 pm]

Zoan -- don't see why not though

[2014-10-06. : 6:45 pm]

Zoan -- I have no idea if I'm allowed to define a multiplicative inverse (1/(x*x)) for (x*x)

[2014-10-06. : 6:44 pm]

Zoan -- so (1/x) > 0

[2014-10-06. : 6:44 pm]

Zoan -- so (x*x)*(1/x) > 0, => (x*x)*(1/(x*x))*(1/x) > 0*(1/(x*x))

[2014-10-06. : 6:43 pm]

Zoan -- Wait, actually just the left side. then I used multiplicative associativity to change it to (x*x)*(1/x) > 0 * (x*(1/x))

[2014-10-06. : 6:42 pm]

jjf28 -- you're not multiplying against 0 are you?

[2014-10-06. : 6:42 pm]

Zoan -- hrm, I multiplied both sides by x(1/x)

[2014-10-06. : 6:40 pm]

jjf28 -- of the right equation that is

[2014-10-06. : 6:39 pm]

jjf28 -- i'd start by adding one to both sides

[2014-10-06. : 6:38 pm]

Zoan -- btw, how do you prove [ x > 0 ] => [ (1/x) > 0 ]

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