I think this is something ridiculously simple but it just slipped out of my mind.
Say you are given an equation:
0.0036 = p(1-cos(0.6/p))
how would you solve for p (note: cos is measured in radians, not degrees)? The answer given is p = 50, but can someone show me the steps?
Post has been edited 2 time(s), last time on Apr 17 2008, 6:09 am by MillenniumArmy.
None.
The book is wrong, by a factor of ten.
None.
This is all I could get:
0.036 = p(1-cos(0.6/p))
0 = p(1-cos(0.6/p)) - 0.036
0 = p - pcos(0.6/p) - 0.036
cos(nx) = 2 cos([n-1]x)cos(x) - cos([n-2]x)
0.6/p = 3/5/p = 3/5p = 6/10p = 1.2/2p = 3/5 * 1/p
3/5/p = 3/p/5
The book is wrong, by a factor of ten.
LOL oops, i meant 0.0036, not 0.036 mb
None.
Expand to Taylor series and approximate.
None.
I think this is something ridiculously simple but it just slipped out of my mind.
Say you are given an equation:
0.0036 = p(1-cos(0.6/p))
how would you solve for p (note: cos is measured in radians, not degrees)? The answer given is p = 50, but can someone show me the steps?
You cannot really solve that, the solution is probably irrational. But you can approximate it by several methods, including Taylor series.
?????
Rantent
MillenniumArmy
NudeRaider -- blessed innocent soul knows nothing of the strife we had before EUDs were discovered 
DarkenedFantasies -- Probably just didn't care. For example, at some point before release, they've updated the graphics of some of the Protoss buildings (Forge, CyberCore, Citadel, Observatory, Arbiter Tribunal), but instead of properly re-rendering them with edited 3D models, they did crappy copy-paste jobs on the rendered graphics.
