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Pages: < 1 � 3375 3376 3377 3378 3379 … 3572 >

[2014-9-23. : 3:55 am]

Zoan -- too*

[2014-9-23. : 3:55 am]

Zoan -- I think ^ is and to

[2014-9-23. : 3:54 am]

Jack -- oh wait maybe ^ = AND, and I've done it completely wrong?

[2014-9-23. : 3:54 am]

Jack -- & presumably = AND

[2014-9-23. : 3:54 am]

O)FaRTy1billion[MM] -- This says p ^ q v r

[2014-9-23. : 3:54 am]

Zoan -- is there a difference between the & and the ^?

[2014-9-23. : 3:54 am]

Jack -- I wrote down the rules in my notebook but that's at home

[2014-9-23. : 3:53 am]

Zoan -- bleh

[2014-9-23. : 3:53 am]

Zoan -- wait no I'm wrong

[2014-9-23. : 3:53 am]

Jack -- not XOR for the first set of parentheses zoan

[2014-9-23. : 3:52 am]

Dem0n -- ;_;

[2014-9-23. : 3:52 am]

Zoan -- (p v q v r) ^ (p v q v ~r) ^ (~p v q v r) = q

[2014-9-23. : 3:52 am]

O)FaRTy1billion[MM] -- this program only accepts A-H, so if I put in (A+B)(A'+B+C) and simplify, it gives me AC+B

[2014-9-23. : 3:50 am]

Zoan -- yea

[2014-9-23. : 3:50 am]

O)FaRTy1billion[MM] -- v is or, ^ is and?

[2014-9-23. : 3:50 am]

Jack -- Dem0n

Dem0n shouted: My expression was (p v q v r) & (p v q v ~r) ^ (~p v q v r)

look at this zoan, I probably screwed it up at every step

[2014-9-23. : 3:50 am]

Zoan -- Whateva, I needa do some set theory crap lulz

[2014-9-23. : 3:49 am]

Zoan --

[2014-9-23. : 3:49 am]

Zoan -- it just simplifies to p v q

[2014-9-23. : 3:49 am]

O)FaRTy1billion[MM] -- And it simplifies it to A'B'C + BD + AC'D'

[2014-9-23. : 3:49 am]

Zoan -- waaaaiiiiittt no it doesn't

[2014-9-23. : 3:48 am]

O)FaRTy1billion[MM] -- Also I'm not crazy, this program uses the A' = not-A notation. xD

[2014-9-23. : 3:48 am]

jjf28 -- lies, cs is math++

[2014-9-23. : 3:48 am]

Zoan -- (p v q) ^ (~p v q v r) reduces to (p v q) ^ r

[2014-9-23. : 3:47 am]

MasterJohnny -- math>cs

[2014-9-23. : 3:45 am]

Jack -- I'd say computer scientists are modern day magicians

[2014-9-23. : 3:45 am]

Jack -- guh I'm too tired and forgot all de rules

[2014-9-23. : 3:44 am]

Jack -- so it's just simplified to 1?

[2014-9-23. : 3:44 am]

Jack -- wait no, expression is always true because those are ors

[2014-9-23. : 3:44 am]

jjf28 -- MasterJohnny

MasterJohnny shouted: cs is toooo nerdy

that attitude is why we can't have nice things

[2014-9-23. : 3:44 am]

O)FaRTy1billion[MM] -- old computer is slow, and bulky software is slow too ;o

[2014-9-23. : 3:44 am]

Jack -- uhhhh so then it's just q v r?

[2014-9-23. : 3:44 am]

Jack -- not used to this method of writing symbols

[2014-9-23. : 3:43 am]

Jack -- (p v q) ^ (~p v q v r) wait those are ors

[2014-9-23. : 3:43 am]

O)FaRTy1billion[MM] -- a xor a is always 0, a xor !a is always 1

[2014-9-23. : 3:43 am]

O)FaRTy1billion[MM] -- yes, it is

[2014-9-23. : 3:43 am]

Zoan -- I think so

[2014-9-23. : 3:43 am]

Jack -- A XOR !A is always true isn't it

[2014-9-23. : 3:43 am]

O)FaRTy1billion[MM] -- I want an expression that defines {a,b,c,d} = r

[2014-9-23. : 3:43 am]

Jack -- wait no

[2014-9-23. : 3:43 am]

Jack -- oh sorry my bad

[2014-9-23. : 3:42 am]

Zoan -- you mean p v ~p lol

[2014-9-23. : 3:42 am]

Jack -- and you end up with just r!

[2014-9-23. : 3:42 am]

Jack -- p ^ ~p will always be true so you get rid of that

[2014-9-23. : 3:42 am]

Zoan -- wheres the r column coming from lol

[2014-9-23. : 3:42 am]

O)FaRTy1billion[MM] -- r is what I want

[2014-9-23. : 3:42 am]

O)FaRTy1billion[MM] -- Because that's what the 'r' column says.

[2014-9-23. : 3:42 am]

MasterJohnny -- cs is toooo nerdy

[2014-9-23. : 3:42 am]

Zoan -- why should it be 0?

[2014-9-23. : 3:42 am]

Jack -- q ^ q is so sirry, so very sirry, so we get rid of that :wtfawesome:

[2014-9-23. : 3:41 am]

O)FaRTy1billion[MM] -- I did them manually... a0 b1 c1 d0 | 0 , (C xor (B and D)) xor A == (1 xor (1 and 0)) xor 0 == (1 xor (0)) xor 0 == (1) xor 0 == 1, but it should be 0 ;o

[2014-9-23. : 3:41 am]

Jack -- Now you have to factor in the xor, so you have (p v q) ^ (~p v q v r)

[2014-9-23. : 3:41 am]

Jack -- so you now have just (p v q)

[2014-9-23. : 3:41 am]

Jack -- now you have (p v q) & (p v q) which is the same as A&A which is the same as just A

[2014-9-23. : 3:40 am]

Jack -- so just get rid of B (aka your original R) because it never affects the result

[2014-9-23. : 3:40 am]

Jack -- see, if A or B has to be true at the same time as A or notB for the expression to be true, then let's say A is 0 and B is 1. The expression will never be B, because it will be like (0 v 1) & (0 v 0), which is not going to work.

[2014-9-23. : 3:40 am]

jjf28 -- http://youtu.be/Unau2Efldqk

[2014-9-23. : 3:40 am]

Zoan -- wherea re you getting the results from?

[2014-9-23. : 3:39 am]

Zoan -- well the long expression not the end there is displaying the correct 1's and 0's

[2014-9-23. : 3:39 am]

O)FaRTy1billion[MM] -- b != r .. ? ;o

[2014-9-23. : 3:38 am]

O)FaRTy1billion[MM] -- dug out my old laptop ... I'd install the program on this computer, but it is one of those softwares that, upon installtion, assumes that is now the sole purpose of that machine and loads so much stuff at startup ;o

[2014-9-23. : 3:38 am]

Jack -- B = your original R

[2014-9-23. : 3:37 am]

Jack -- Or rather, it's silly!

[2014-9-23. : 3:37 am]

Jack -- @Dem0n but then you can see that B breaks everything

[2014-9-23. : 3:37 am]

O)FaRTy1billion[MM] -- it's the expected result I'm trying to find

[2014-9-23. : 3:37 am]

O)FaRTy1billion[MM] -- Oh, I just called it that for 'result'

[2014-9-23. : 3:36 am]

Zoan -- FaRTy1billion

FaRTy1billion shouted: http://i.snag.gy/4G3RN.jpg

in this

[2014-9-23. : 3:36 am]

Zoan -- whats that r there?

[2014-9-23. : 3:36 am]

MasterJohnny -- and Xor or?

[2014-9-23. : 3:36 am]

Jack -- Dem0n first look at (p v q v r) & (p v q v ~r), you can think of this as being (A v B) & (A v ~B)

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