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[2014-10-21. : 2:10 pm]  Azrael -- Of course, they could always do a "100% vote needed to surrender, and 3/5 people on the opposing team need to accept it".[2014-10-21. : 2:10 pm] Azrael -- Which would make the game less fun for the opponents who wanted to crush you xD[2014-10-21. : 2:09 pm] Azrael -- As opposed to "Aw, we started to lose, our chances aren't great. Let's just surrender and go to the next game."[2014-10-21. : 2:08 pm] Azrael -- It ensures you'll scramble and struggle to the very last moment to try to push back and not be crushed.[2014-10-21. : 2:08 pm] Azrael -- GeneralpieGeneralpie shouted: Considering my very first match against humans was 25 minutes of play time, and 20 minutes of camping the spawn. But a situation like that motivates you to try harder.[2014-10-21. : 11:58 am]  Generalpie -- Considering my very first match against humans was 25 minutes of play time, and 20 minutes of camping the spawn.[2014-10-21. : 11:44 am] Generalpie -- DOTA 2 is cool. The only thing it needs is a surrender button...[2014-10-21. : 6:33 am]  O)FaRTy1billion[MM] -- l)ark_ssj9kevinl)ark_ssj9kevin shouted: if this is unsigned you can do ~0U to get all 1's, regardless of what size integer it is I just use -1./[2014-10-21. : 5:03 am] poiuy_qwert -- thats the thing, the question is wrong. its should be getSecondNibbleFromLR[2014-10-21. : 5:02 am] Dem0n -- if a short byte is only 2 bytes, how does shifting the bits by 12 work?[2014-10-21. : 4:59 am] poiuy_qwert -- it depends on the size of the variable thats storing that number[2014-10-21. : 4:57 am] Dem0n -- if you had like 0x1f, would that be represented as 0000000000011111>[2014-10-21. : 4:53 am] poiuy_qwert -- ((0000111100000000 << 4) >> 12) == (1111000000000000 >> 12) == 0000000000001111[2014-10-21. : 4:47 am] Dem0n -- Unless I don't actually get my it's being shifted to the left 4, in which case I would definitely not know why it's shifted to the right 12 times[2014-10-21. : 4:46 am] Dem0n -- I get why you shift it to the left 4 bits, but I don't understand what shifting it to the right 12 bits accomplishes[2014-10-21. : 4:36 am] NudeRaider -- jj, just create the username of what you want to quote - problem solved.  [2014-10-21. : 4:33 am] jjf28 -- don't see it in the documentation... ferror might be set (conditions for ferror? can't find them)[2014-10-21. : 4:29 am] Dem0n -- if you input an int and a double, but scanf is expecting two ints, will it return 1, 2, or will there be an error?[2014-10-21. : 4:23 am] jjf28 -- I want candy... tempted to be that creepy 20yr old out trick 'or' treating without a kid  [2014-10-21. : 4:08 am] Dem0n -- I was like why would you AND it by 1 because if you're rotating from the left you'll just get 00000000 lul[2014-10-21. : 4:07 am] poiuy_qwert -- and as farty was saying, if you need to do it to the left, you need to grab the leftmost bit, which would be (a & 128)[2014-10-21. : 4:01 am] poiuy_qwert -- since its shifting to the right, its grabbing the rightmost bit since it will be dropped[2014-10-21. : 4:00 am] Dem0n -- poiuy_qwertpoiuy_qwert shouted: so for correctness: ((a & 1) << 7) | (a >> 1) What does ANDing a by 1 do?[2014-10-21. : 4:00 am] l)ark_ssj9kevin -- i remember rotating bits was an exercise in k&r, it was kinda fun[2014-10-21. : 3:55 am] Dem0n -- well I mean I was just writing 11000010 and then dropping those 1's when I shifted it, which obviously isn't correct[2014-10-21. : 3:51 am] jjf28 -- you can go without, good habit to write them in if others see your work though[2014-10-21. : 3:49 am] l)ark_ssj9kevin -- if this is unsigned you can do ~0U to get all 1's, regardless of what size integer it is |
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